Research Paper Topics In Wireless Networks And Telecommunications System
Wednesday, May 20, 2020
Math 533 Part B - 1210 Words
PROJECT PART B: Hypothesis Testing and Confidence Intervals Math-533 Applied Managerial Statistics Prof. Jeffrey Frakes December 8, 2014 Jared D Stock A.) The average (mean) annual income was greater than $45,000 Null Hypothesis: The average (mean) annual income is greater than or equal to $45,000. Ho: u $45,000 Alternative Hypothesis: The average (mean) annual income was less than $45,000 Ha: u $45,000 I will use a = .05 as the significance level, and observing the sample size of n 30 which tells me I need to use a Z-Test to find the mean of this test and the hypothesis. As the alternative hypothesis is Ha: u $45,000, the given test is a one-tailed Z-Test. The critical value for theâ⬠¦show more contentâ⬠¦Ho: u 8 Alternate Hypothesis: The average (mean) number of years lived in the current home is greater than 8 years. Ha: u 8 I will utilize, à ±=0.05. Because the sample size is less than 30, a Z-Test will be utilized to find the mean of the hypothesis. As the alternative hypothesis is Ha: u 8, the given test is a one-tailed Z-Test. The critical value for significance level, à ±=0.05 for a lower-tailed z-test is given as 1.645. Decision Rule: Reject null hypothesis z 1.645 Test Statistic from Minitab: One-Sample Z: Years Test of mu = 8, 8 The proposed standard deviation = 4.4855 95% Upper Variable N Mean StDev SE Mean Bound Z P Years 50 12.380 4.4855 0.722 8.557 2.52 0.006 Summary Since the value of the test statistic is in the critical region, I am rejecting the null hypothesis. Therefore, I can conclude the data gives enough evidence to show the null hypothesis is false. I can say with 95% confidence or 5% significance the claim, the average (mean) number of years lived in the current home is greater than 8 years, is true. So the p-value for this test is 0.006. Which is smaller than the significance level 0.05, as a result I am rejecting the null hypothesis based on the p-value approach as well. The 95% Lower Confidence Bound in this case is 8.557;Show MoreRelatedKeller Math 533 Project Part B1734 Words à |à 7 PagesMath 533 Project Part B In regards to the dataset from AJ Department store, your manager has speculated the following: the average (mean) annual income is less than $50,000, the true population proportion of customers who live in an urban area exceeds 40%, the average (mean) number of years lived in the current home is less than 13 years, the average (mean) credit balance for suburban customers is more than $4300. Part 1. Using the sample data, performRead MoreMath 533 Course Project Part B Essay1482 Words à |à 6 PagesAJ DAVIS AJ DAVIS MATH 533 Project Consumer Tel ââ¬â 123-456-7891 July 21st 2013 MATH 533 Project Consumer Tel ââ¬â 123-456-7891 July 21st 2013 Lakshan Nanayakkara AJ DAVIS is a department store chain, which has many credit customers. 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Degree in Automotive Engineering requires a total of 30 creditsââ¬â27 of which must be letter (A-E) graded. A minimum grade point average of 5.0/9.0 (ââ¬Å"Bâ⬠average) is required for graduation. Of the 30 credit hours, 24 must be 500 level or above. At most, 6 credit hours can be at the 400-level. SYSTEMS ENGINEERING CORE (9 credits) Courses must be taken in each area. 1. Powertrain AUTO 563 DynamicsRead MoreEssay about Equal Gender Representation in The Gaming Franchise2431 Words à |à 10 Pagesbeloved by their followers that the annual Entertainment Software Association reports the gaming industry at an estimated $17 billion dollars franchise; globally that number increases to $67 billion of which 48% is female and 52% male. Females are also part of the gaming population, representing 47% while the males represent 53% (E.S.A., 2012). 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